మాడ్యూల్:Factorization
This module is rated as beta, and is ready for widespread use. It is still new and should be used with some caution to ensure the results are as expected. |
This template displays the factorization of a given number. Numbers smaller than 2 or greater than 1,000,000,000 return "number out of range". Fractional numbers are rounded down.
- Parameters
- The first unnamed parameter is the number
- Product - the symbol to be used to indicate times. Defaults to ·
- Bold - set to any value to make it bold
- Serif - set to any value to make it serif
- Big - set to any value to make it big
- Prime - set to any value to have prime numbers return an unformatted link to prime instead of the number
local p = {}
function p.factor(frame)
number = tonumber(frame.args[1])
productSymbol = frame.args['product'] or '·'
bold = frame.args['bold'] and true
big = frame.args['big'] and true
serif = frame.args['serif'] and true
primeLink = frame.args['prime'] and true
number = math.floor(number)
if number < 2 or number > 1000000000 then
return '<strong class="error">number out of range</strong>'
end
result = ""
currentNumber = number
power = 0
--First take care of 2, the only even prime number.
if currentNumber % 2 == 0 then
result = '2'
currentNumber = currentNumber / 2
power = 1
end
while currentNumber % 2 == 0 do
currentNumber = currentNumber / 2
power = power + 1
end
if power > 1 then
result = result..'<sup>'..power..'</sup>'..productSymbol..' '
elseif power == 1 then
result = result..' '..productSymbol..' '
end
--Now do all odd numbers.
prime = 3
while prime <= math.sqrt(currentNumber) do
power = 0
if currentNumber % prime == 0 then
result = result..prime
currentNumber = currentNumber / prime
power = 1
end
while currentNumber % prime == 0 do
currentNumber = currentNumber / prime
power = power + 1
end
if power > 1 then
result = result..'<sup>'..power..'</sup>'..productSymbol..' '
elseif power == 1 then
result = result..' '..productSymbol..' '
end
prime = prime + 2
end
if currentNumber ~= 1 then
result = result..currentNumber..' '..productSymbol..' '
end
if currentNumber == number and primeLink then
return '[['..'prime'..']]'
end
result = string.sub(result,1,-4)
return format(result)
end
function format(num)
if bold then
num = '<b>'..num..'</b>'
end
if serif then
if big then
num = '<span class="texhtml" style="font-size:165%">'..num..'</span>'
else
num = '<span class="texhtml">'..num..'</span>'
end
elseif big then
num = '<span style="font-size:165%">'..num..'</span>'
end
return num
end
return p